(dy)/(dθ)=sin(θ)

解答

\frac{d y}{d θ} = sin (θ)

y = - cos (θ) + c_{1}

求解步骤

\frac{d y}{d θ} = sin (θ)

替代

\frac{d y}{d θ}

与

y^{'} (θ)

y^{^{'}} (θ) = sin (θ)

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int sin (θ) d θ

\int sin (θ) d θ = - cos (θ) + c_{1}

y = - cos (θ) + c_{1}

\int x e^{x y} + 2 x y + \frac{1}{x}

x \to - 2 lim (\frac{( x - 2 )}{x + 2})

\int_{- 3}^{5} (1 + 4 x) d x

\int sin (x) sin (x) d x

t an g e n t y = ln (x^{2}), at x = 4