laplacetransform e^{1-2t}

Lösung

laplace transformation

e^{1 - 2 t}

\frac{e}{s + 2}

Schritte zur Lösung

L {e^{1 - 2 t}}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{1} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{1} \frac{1}{s + 2}

Fasse

e^{1} \frac{1}{s + 2}

zusammen:

\frac{e}{s + 2}

= \frac{e}{s + 2}

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