zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的微积分 >

ds=2sqrt(s)dt

解答

d s = 2 s d t

解答

t = s + c_{1}

求解步骤

d s = 2 s d t

令

t

为因变量。除以

d s

:

1 = 2 s \frac{d t}{d s}

用

t^{'} (s)

替代

\frac{d t}{d s}

1 = 2 s t^{^{'}} (s)

整理

t^{'} (s) : t^{'} (s) = \frac{1}{2 s}

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

t = \int \frac{1}{2 s} d s

\int \frac{1}{2 s} d s = s + c_{1}

t = s + c_{1}

作图

流行的例子

sum from n=0 to infinity of 5(-1/3)^n

n = 0 \sum \infty 5 (- \frac{1}{3})^{n}

limit as x approaches 4 of ((x^2-16))/(2-sqrt(x))

x \to 4 lim (\frac{( x ^{2} - 16 )}{2 - x})

derivative of ln(2e^{-x}sin(x))

\frac{d}{d x} (ln (2 e^{- x} sin (x)))

integral of sqrt(1+(tan(x))^2)

\int 1 + (tan (x))^{2} d x

derivative g(x)=sqrt(6-x)

d er i v a t i v e g (x) = 6 - x