derivative of 4x^2+3x-7

解答

\frac{d}{d x} (4 x^{2} + 3 x - 7)

8 x + 3

求解步骤

\frac{d}{d x} (4 x^{2} + 3 x - 7)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (7)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (7) = 0

= 8 x + 3 - 0

化简

= 8 x + 3

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