y^'+4y=3sin(e^4x)

Lösung

y^{^{'}} + 4 y = 3 sin (e^{4} x)

y = \frac{\int 3 sin ( e ^{4} x ) e ^{4 x} d x}{e ^{4 x}}

Schritte zur Lösung

y^{'} (x) + 4 y = 3 sin (e^{4} x)

Solve linear ODE:

y = \frac{\int 3 sin ( e ^{4} x ) e ^{4 x} d x}{e ^{4 x}}

y = \frac{\int 3 sin ( e ^{4} x ) e ^{4 x} d x}{e ^{4 x}}

\int x^{m} d x

\int \frac{1}{x ^{4} + 4 x ^{2}} d x

y^{^{''}} + 2 y^{^{'}} + 5 y = 4 e^{- t} cos (2 t)

x \cdot d x - y^{2} \cdot d y = 0

y^{^{'}} = x^{2} + 1