laplacetransform [\delta(t+1)]

解答

拉普拉斯变换

[δ (t + 1)]

1

求解步骤

L {δ (t + 1)}

化简

= L {δ (t - (- 1))}

使用拉普拉斯变换表:

L {δ (t - c)} = 1, c \leq 0

L {δ (t + 1)} = 1

= 1

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