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Beliebt Rechnen >

laplacetransform e^{2t}sin(2tj)

Lösung

laplace transformation

e^{2 t} sin (2 t j)

Lösung

\frac{2 j}{( s - 2 ) ^{2} + 4 j ^{2}}

Schritte zur Lösung

L {e^{2 t} sin (2 j t)}

Wende Transformationsregel an: wenn

L {f (t)} = F (s)

dann

L {e^{a t} f (t)} = F (s - a)

Für

e^{2 t} sin (2 t j) : f (t) = sin (2 t j), a = 2

= L {sin (2 t j)} (s - 2)

L {sin (2 t j)} : \frac{2 j}{s ^{2} + 4 j ^{2}}

= \frac{2 j}{( s - 2 ) ^{2} + 4 j ^{2}}

Beliebte Beispiele

derivative y=ccos(t)+t^2sin(t)

d er i v a t i v e y = c cos (t) + t^{2} sin (t)

(\partial)/(\partial y)(x+2y+1)

\frac{\partial}{\partial y} (x + 2 y + 1)

laplacetransform 6cos(4t-1)

l a pl a ce t r an s f or m 6 cos (4 t - 1)

integral from 0 to 3 of-2x

\int_{0}^{3} - 2 x d x

tangent f(x)=x^4+9e^x,\at x=0

t an g e n t f (x) = x^{4} + 9 e^{x}, at x = 0