What is the integral from 7 to 2 of g(x) ?

The integral from 7 to 2 of g(x) is -(45g)/2

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integral from 7 to 2 of g(x)

\int_{7}^{2} g (x) d x

- \frac{45 g}{2}

Solution steps

\int_{7}^{2} gx d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{2}^{7} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - g \cdot \int_{2}^{7} x d x

Apply the Power Rule

= - g [\frac{x ^{2}}{2}]_{2}^{7}

Compute the boundaries:

\frac{45}{2}

= - g \frac{45}{2}

Simplify

= - \frac{45 g}{2}

\frac{d}{d x} (cos (2 x) - 2 x sin (2 x))

\int \frac{22 x + 88}{2 x ^{2} + 9 x - 5} d x

\int u^{- \frac{3}{2}} d u

d er i v a t i v e y = csc^{2} (x)

\int x (x + 5) d x

What is the integral from 7 to 2 of g(x) ?
The integral from 7 to 2 of g(x) is -(45g)/2