derivative of e^{9xsin(2x})

Lösung

\frac{d}{d x} (e^{9 x s i n (2 x)})

e^{9 x s i n (2 x)} \cdot 9 (sin (2 x) + 2 x cos (2 x))

Schritte zur Lösung

\frac{d}{d x} (e^{9 x s i n (2 x)})

Wende die Kettenregel an:

e^{9 x s i n (2 x)} \frac{d}{d x} (9 x sin (2 x))

= e^{9 x s i n (2 x)} \frac{d}{d x} (9 x sin (2 x))

\frac{d}{d x} (9 x sin (2 x)) = 9 (sin (2 x) + 2 x cos (2 x))

= e^{9 x s i n (2 x)} \cdot 9 (sin (2 x) + 2 x cos (2 x))

n = 1 \sum \infty \frac{cos ( n )}{n ^{5}}

\frac{d}{d x} (lo g_{10} ((x^{2} + 1)^{2}))

\int x - cos (x) d x

in v erse l a pl a ce e^{- s} \frac{( s ^{2} + 2 )}{s ^{3}}

\int \frac{1}{y + y ^{3}} d y