y^{''}-2y^'+1=0

Lösung

y^{^{''}} - 2 y^{^{'}} + 1 = 0

y = c_{1} e^{2 t} + c_{2} + \frac{t}{2}

Schritte zur Lösung

y^{''} (t) - 2 y^{'} (t) + 1 = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} + \frac{t}{2}

y = c_{1} e^{2 t} + c_{2} + \frac{t}{2}

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