(\partial)/(\partial x)(ln(axy)+b^{xy})

Lösung

\frac{\partial}{\partial x} (ln (a x y) + b^{x y})

\frac{1}{x} + y b^{y x} ln (b)

Schritte zur Lösung

\frac{\partial}{\partial x} (ln (a x y) + b^{x y})

Behandle

a, y, b

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (a x y)) + \frac{\partial}{\partial x} (b^{x y})

\frac{\partial}{\partial x} (ln (a x y)) = \frac{1}{x}

\frac{\partial}{\partial x} (b^{x y}) = y b^{y x} ln (b)

= \frac{1}{x} + y b^{y x} ln (b)

a re a 220 + 11 x - 11 x^{2}, 11 x^{2} - 55 x

d er i v a t i v e x^{5} e^{x}

\int 2 \cdot (x - 6)^{3} d x

t an g e n t f (x) = 7 + 4 x^{2} - 2 x^{3}, at x = a

d er i v a t i v e 4 e^{x^{- 3}}