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Popular Calculus >

expand 4x^2(3x^3-2x^2+5x)

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Solution

expand 4x2(3x3−2x2+5x)

Solution

12x5−8x4+20x3
Solution steps
4x2(3x3−2x2+5x)
Apply the distributive law: m(a+b+c)=ma+mb+mc4x2(3x3−2x2+5x)=4x2⋅3x3+4x2(−2x2)+4x2⋅5x=4x2⋅3x3+4x2(−2x2)+4x2⋅5x
Simplify 4x2⋅3x3+4x2(−2x2)+4x2⋅5x:12x5−8x4+20x3
=12x5−8x4+20x3

Popular Examples

integral of (7x^2-4)^2x^3∫(7x2−4)2x3dxlimit as x approaches 6 of 1+csc(2x)x→6lim​(1+csc(2x))integral of (-9x+27)/(2x-3)∫2x−3−9x+27​dxintegral of (x+1)y^2sin((xy)/3)∫(x+1)y2sin(3xy​)dxsum from n=1 to infinity of (n-5)/(n+5)n=1∑∞​n+5n−5​

Frequently Asked Questions (FAQ)

  • What is expand 4x^2(3x^3-2x^2+5x) ?

    The solution to expand 4x^2(3x^3-2x^2+5x) is 12x^5-8x^4+20x^3
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