y^{''}+9y=0,y(0)=8,y^'(0)=7

Lösung

y^{^{''}} + 9 y = 0, y (0) = 8, y^{^{'}} (0) = 7

y = 8 cos (3 t) + \frac{7}{3} sin (3 t)

Schritte zur Lösung

y^{''} (t) + 9 y = 0

Solve linear ODE:

y = 8 cos (3 t) + \frac{7}{3} sin (3 t)

y = 8 cos (3 t) + \frac{7}{3} sin (3 t)

in v erse l a pl a ce \frac{\frac{1}{500}}{140 + 8 s + s ^{2}}

\int (2 x - \frac{1}{2 x}) d x

y^{^{''}} + 6.2832 y = 10

d er i v a t i v e y = x^{2} (x + 3)

x \to \infty lim (1.9)