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Beliebt Rechnen >

sum from n=1 to infinity of (1/6)^n

Lösung

n = 1 \sum \infty (\frac{1}{6})^{n}

Lösung

\frac{1}{5}

+1

Dezimale

0.2

Schritte zur Lösung

n = 1 \sum \infty (\frac{1}{6})^{n}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty (\frac{1}{6})^{n} - (\frac{1}{6})^{0}

n = 0 \sum \infty (\frac{1}{6})^{n} = \frac{6}{5}

= \frac{6}{5} - (\frac{1}{6})^{0}

Vereinfache

\frac{6}{5} - (\frac{1}{6})^{0} : \frac{1}{5}

= \frac{1}{5}

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