sum from n=4 to infinity of 1/(n^2+n)

Lösung

n = 4 \sum \infty \frac{1}{n ^{2} + n}

\frac{1}{4}

Dezimale

0.25

Schritte zur Lösung

n = 4 \sum \infty \frac{1}{n ^{2} + n}

Teleskopreihen-Test anwenden:

\frac{1}{4}

= \frac{1}{4}

x \to 3 lim (\frac{x + 2}{x - 3})

x \to 9 + lim (\frac{x - 9}{∣ x - 9 ∣})

y^{^{''}} + 6 y^{^{'}} + 9 y = 12 e^{- x}

\frac{d}{d x} (cos (\frac{1 - e ^{8 x}}{1 + e ^{8 x}}))

\int \frac{z}{1 0 ^{z}} d z