What is the derivative of (x^2-1^3) ?

The derivative of (x^2-1^3) is 6x(x^2-1)^2

What is the first derivative of (x^2-1^3) ?

The first derivative of (x^2-1^3) is 6x(x^2-1)^2

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\frac{d}{d x} ((x^{2} - 1)^{3})

6 x (x^{2} - 1)^{2}

Solution steps

\frac{d}{d x} ((x^{2} - 1)^{3})

Apply the chain rule:

3 (x^{2} - 1)^{2} \frac{d}{d x} (x^{2} - 1)

= 3 (x^{2} - 1)^{2} \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= 3 (x^{2} - 1)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} - 1)^{2}

\frac{1}{t ^{2} - 1}

\int \frac{7 x - 1}{x ^{2} - 1} d x

f (x) = 4 x + 1

\int \frac{( x ^{3} + 16 )}{x ^{2} + 16} d x

\int - tan (x) + C d x

What is the derivative of (x^2-1^3) ?
The derivative of (x^2-1^3) is 6x(x^2-1)^2
What is the first derivative of (x^2-1^3) ?
The first derivative of (x^2-1^3) is 6x(x^2-1)^2