derivative f(x)=-16x^{3/2}+6x^{1.7}+x

Lösung

ableitung von

f (x) = - 16 x^{\frac{3}{2}} + 6 x^{1.7} + x

- 24 x^{\frac{1}{2}} + 10.2 x^{0.7} + 1

Schritte zur Lösung

\frac{d}{d x} (- 16 x^{\frac{3}{2}} + 6 x^{1.7} + x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (16 x^{\frac{3}{2}}) + \frac{d}{d x} (6 x^{1.7}) + \frac{d x}{d x}

\frac{d}{d x} (16 x^{\frac{3}{2}}) = 24 x^{\frac{1}{2}}

\frac{d}{d x} (6 x^{1.7}) = 10.2 x^{0.7}

\frac{d x}{d x} = 1

= - 24 x^{\frac{1}{2}} + 10.2 x^{0.7} + 1

\frac{d}{d x} ((cos (x))^{x})

t an g e n t \frac{( x - 1 )}{x + 1}

t an g e n t - 7 x^{4} + 11 x^{2} - 4

\int \frac{x ^{2}}{( 1 + 9 x ^{2} ) ^{\frac{3}{2}}} d x

x \to 6 lim ((x - 2)^{2})