derivative of 5x^3+2x^2+6x+10

Lösung

\frac{d}{d x} (5 x^{3} + 2 x^{2} + 6 x + 10)

15 x^{2} + 4 x + 6

Schritte zur Lösung

\frac{d}{d x} (5 x^{3} + 2 x^{2} + 6 x + 10)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{3}) + \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (10)

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (10) = 0

= 15 x^{2} + 4 x + 6 + 0

Vereinfache

= 15 x^{2} + 4 x + 6

d er i v a t i v e g (x) = \frac{1}{5 x ^{2} + 3 x}

x \to \infty lim (x^{- 7})

\frac{d}{d x} (sin (cos (x^{2} + 3 x)))

\frac{d}{d x} (- sec (x) + 2 sec^{3} (x))

\frac{d}{d x} (8 x \cdot sin (x))