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面积 y^2=x+4,y^2=2-x

解答

面积

y^{2} = x + 4, y^{2} = 2 - x

解答

无解

求解步骤

对于

y^{2} = x + 4

将

y

移到一边:

y = x + 4, y = - x + 4

对于

y^{2} = 2 - x

将

y

移到一边:

y = 2 - x, y = - 2 - x

f_{1} (x) = x + 4

f_{2} (x) = - x + 4

要找到相交点，解

f_{i} (x) = f_{j} (x)

x + 4 = - x + 4 : x = - 4

x + 4 = 2 - x : x = - 1

x + 4 = - 2 - x : x \in R

无解

- x + 4 = 2 - x : x \in R

无解

- x + 4 = - 2 - x : x = - 1

2 - x = - 2 - x : x = 2

曲线没有界限

= 无解

作图

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