What is (\partial)/(\partial x)(2y^2-3x^2-z) ?

The answer to (\partial)/(\partial x)(2y^2-3x^2-z) is -6x

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(\partial)/(\partial x)(2y^2-3x^2-z)

\frac{\partial}{\partial x} (2 y^{2} - 3 x^{2} - z)

- 6 x

Solution steps

\frac{\partial}{\partial x} (2 y^{2} - 3 x^{2} - z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y^{2}) - \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (z)

\frac{\partial}{\partial x} (2 y^{2}) = 0

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (z) = 0

= 0 - 6 x - 0

Simplify

= - 6 x

\frac{d}{d x} (lo g_{e} (x^{2} + 1))

y = (tan (- 1 (3 x))) 2

x x

- 0.6 t^{2} + 30 t

\int_{0}^{5} π (- \frac{3}{5} x + 3)^{2} d x

What is (\partial)/(\partial x)(2y^2-3x^2-z) ?
The answer to (\partial)/(\partial x)(2y^2-3x^2-z) is -6x