limit as x approaches-1-of (x-1)/(x+1)

解答

x \to - 1 - lim (\frac{x - 1}{x + 1})

\infty

求解步骤

x \to - 1 - lim (\frac{x - 1}{x + 1})

\frac{x - 1}{x + 1} = (x - 1) \frac{1}{x + 1}

= x \to - 1 - lim ((x - 1) \frac{1}{x + 1})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

不定型除外

= x \to - 1 - lim (x - 1) \cdot x \to - 1 - lim (\frac{1}{x + 1})

x \to - 1 - lim (x - 1) = - 2

x \to - 1 - lim (\frac{1}{x + 1}) = - \infty

= (- 2) (- \infty)

运用无穷大属性:

- c \cdot (- \infty) = \infty

= \infty

(2 x y + 3 y^{2}) d x - (x^{2} + 2 x y) d y = 0

d er i v a t i v e 10 e^{10 x}

\frac{\partial}{\partial m} (\frac{G ( m , r ) m}{r ^{2}})

x \to 0 - lim (x \cdot e^{\frac{1}{x}})

d er i v a t i v e \frac{1 - 6 t}{4 + t}