derivative of (x^2-2x+1/(x+1))

Lösung

\frac{d}{d x} (\frac{x ^{2} - 2 x + 1}{x + 1})

\frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{2} - 2 x + 1}{x + 1})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 2 x + 1 ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x ^{2} - 2 x + 1 )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x^{2} - 2 x + 1) = 2 x - 2

\frac{d}{d x} (x + 1) = 1

= \frac{( 2 x - 2 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 2 x + 1 )}{( x + 1 ) ^{2}}

Vereinfache

\frac{( 2 x - 2 ) ( x + 1 ) - 1 \cdot ( x ^{2} - 2 x + 1 )}{( x + 1 ) ^{2}} : \frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}}

= \frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}}

\int_{- \infty}^{- 3} x e^{x} d x

\int \frac{y}{y + 2} d y

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