derivative e^{3tsin(2t)}

Lösung

ableitung von

e^{3 t s i n (2 t)}

e^{3 t s i n (2 t)} \cdot 3 (sin (2 t) + 2 t cos (2 t))

Schritte zur Lösung

\frac{d}{d t} (e^{3 t s i n (2 t)})

Wende die Kettenregel an:

e^{3 t s i n (2 t)} \frac{d}{d t} (3 t sin (2 t))

= e^{3 t s i n (2 t)} \frac{d}{d t} (3 t sin (2 t))

\frac{d}{d t} (3 t sin (2 t)) = 3 (sin (2 t) + 2 t cos (2 t))

= e^{3 t s i n (2 t)} \cdot 3 (sin (2 t) + 2 t cos (2 t))

x \to 7 + lim (ln (x^{2} - 49))

\int 4 x^{9} d x

a re a y = sin^{2} (x), y = sin^{3} (x), x = 0, x = π

y^{^{''}} + 400 y = sec (20 x)

x \to - 3 + lim (4 x^{2} - 7)