derivative of (2x-1/(x^2))

Lösung

\frac{d}{d x} (\frac{2 x - 1}{x ^{2}})

\frac{2 ( - x + 1 )}{x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (\frac{2 x - 1}{x ^{2}})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 1 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( 2 x - 1 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (2 x - 1) = 2

\frac{d}{d x} (x^{2}) = 2 x

= \frac{2 x ^{2} - 2 x ( 2 x - 1 )}{( x ^{2} ) ^{2}}

Vereinfache

\frac{2 x ^{2} - 2 x ( 2 x - 1 )}{( x ^{2} ) ^{2}} : \frac{2 ( - x + 1 )}{x ^{3}}

= \frac{2 ( - x + 1 )}{x ^{3}}

\int 8 x + 9 d x

\int e^{θ} cos (2 θ) d θ

\frac{d ^{2}}{d x ^{2}} ((1 + \frac{1}{x})^{3})

t an g e n t f (x) = x^{2} + 2, (- 3, 11)

\frac{\partial}{\partial x} (x e^{y} + y e^{z} + z e^{x})