derivative f(x)=x^2+x-9

Lösung

ableitung von

f (x) = x^{2} + x - 9

2 x + 1

Schritte zur Lösung

\frac{d}{d x} (x^{2} + x - 9)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (9) = 0

= 2 x + 1 - 0

Vereinfache

= 2 x + 1

x \to \frac{1}{8} lim (\frac{1}{x} + x^{- 1})

\int \frac{1}{t ^{2} + 9} d t

\int (4 x^{3} + x^{2}) (3 x^{4} + x^{3})^{8} d x

\int \frac{1}{z ^{3} z ^{2} - 100} d z

\frac{\partial}{\partial x} (x^{2} y - 3 x y + x y^{2})