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Beliebt Rechnen >

y^'+2y=0,y(0)=1

Lösung

y^{^{'}} + 2 y = 0, y (0) = 1

Lösung

y = e^{- 2 t}

Schritte zur Lösung

y^{'} (t) + 2 y = 0

Solve separable ODE:

y = e^{- 2 t}

y = e^{- 2 t}

Graph

Beliebte Beispiele

4y^{''}+4y^'+17=0

4 y^{^{''}} + 4 y^{^{'}} + 17 = 0

derivative of (x+7/(4x^2e^x))

\frac{d}{d x} (\frac{x + 7}{4 x ^{2} e ^{x}})

tangent (x^3+2)^5,\at x=-1

t an g e n t (x^{3} + 2)^{5}, at x = - 1

(\partial)/(\partial x)(56y^4x^6-42y^3x^5)

\frac{\partial}{\partial x} (56 y^{4} x^{6} - 42 y^{3} x^{5})

derivative (x-1)^2(x-2)^3

d er i v a t i v e (x - 1)^{2} (x - 2)^{3}