What is the derivative of y=-(x-2)^2+16 ?

The derivative of y=-(x-2)^2+16 is -2x+4

What is the first derivative of y=-(x-2)^2+16 ?

The first derivative of y=-(x-2)^2+16 is -2x+4

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derivative of

y = - (x - 2)^{2} + 16

- 2 x + 4

Solution steps

\frac{d}{d x} (- (x - 2)^{2} + 16)

Simplify

- (x - 2)^{2} + 16 : - x^{2} + 4 x + 12

= \frac{d}{d x} (- x^{2} + 4 x + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (12)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (12) = 0

= - 2 x + 4 + 0

Simplify

= - 2 x + 4

\int \frac{8 x + 28}{x ^{2} + 8 x + 12} d x

\int \frac{x + 7}{2 x ^{3} - 8 x} d x

\int_{0}^{\infty} \frac{9}{x ^{2} + 4} d x

(4, 2), (- 16, - 10)

t^{- \frac{1}{2}}

What is the derivative of y=-(x-2)^2+16 ?
The derivative of y=-(x-2)^2+16 is -2x+4
What is the first derivative of y=-(x-2)^2+16 ?
The first derivative of y=-(x-2)^2+16 is -2x+4