f^'(x)=1.9181x^2+177.69x-0.4*x^3

解

f^{^{'}} (x) = 1.9181 \cdot x^{2} + 177.69 \cdot x - 0.4 \cdot x^{3}

f (x) = 0.63936 \dots x^{3} + 88.845 x^{2} - 0.1 x^{4} + c_{1}

解答ステップ

f^{'} (x) = 1.9181 \cdot x^{2} + 177.69 \cdot x - 0.4 \cdot x^{3}

f^{^{'}} (x) = g (x)

であれば

f (x) = \int g (x) d x

f (x) = \int 1.9181 x^{2} + 177.69 x - 0.4 x^{3} d x

\int 1.9181 x^{2} + 177.69 x - 0.4 x^{3} d x = 0.63936 \dots x^{3} + 88.845 x^{2} - 0.1 x^{4} + c_{1}

f (x) = 0.63936 \dots x^{3} + 88.845 x^{2} - 0.1 x^{4} + c_{1}