derivative 1/2 t^2-6t+23

解

導関数

\frac{1}{2} t^{2} - 6 t + 23

t - 6

解答ステップ

\frac{d}{d t} (\frac{1}{2} t^{2} - 6 t + 23)

簡素化

\frac{1}{2} t^{2} - 6 t + 23 : \frac{t ^{2}}{2} - 6 t + 23

= \frac{d}{d t} (\frac{t ^{2}}{2} - 6 t + 23)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{t ^{2}}{2}) - \frac{d}{d t} (6 t) + \frac{d}{d t} (23)

\frac{d}{d t} (\frac{t ^{2}}{2}) = t

\frac{d}{d t} (6 t) = 6

\frac{d}{d t} (23) = 0

= t - 6 + 0

簡素化

= t - 6