What is the tangent of f(x)= 1/(2sqrt(x)),\at x=100 ?

The tangent of f(x)= 1/(2sqrt(x)),\at x=100 is y=-1/4000 x+3/40

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tangent of f(x)= 1/(2sqrt(x)),\at x=100

tangent of

f (x) = \frac{1}{2 x}, at x = 100

y = - \frac{1}{4000} x + \frac{3}{40}

Solution steps

Find the tangent point:

(100, \frac{1}{20})

Find the slope of

f (x) = \frac{1}{2 x} : \frac{df ( x )}{d x} = - \frac{1}{4 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{4000}

Find the line with slope m=

- \frac{1}{4000}

and passing through

(100, \frac{1}{20}) : y = - \frac{1}{4000} x + \frac{3}{40}

y = - \frac{1}{4000} x + \frac{3}{40}

sin (e^{- 2 q})

\int (cos^{2} (2 x)) d x

\frac{\partial}{\partial y} (x^{2} y e^{x})

(0) (2.6)

n = 1 \sum \infty 4 (\frac{1}{4})^{n}

What is the tangent of f(x)= 1/(2sqrt(x)),\at x=100 ?
The tangent of f(x)= 1/(2sqrt(x)),\at x=100 is y=-1/4000 x+3/40