integral from 0 to 2 of (x)

Lösung

\int_{0}^{2} (x) d x

2

Schritte zur Lösung

\int_{0}^{2} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{0}^{2}

Berechne die Grenzen:

2

= 2

\int e^{2 θ} + e^{2 θ} d θ

y^{- 2} \frac{d y}{d x} + y^{- 1} = 2 x

\frac{\partial}{\partial x} (e^{3 x} tan (y))

y^{^{''}} + 6 y^{^{'}} - 16 y = 0

\frac{\partial}{\partial x} (ln (tan (x)))