integral of sec^2(x)+tan(x)

Lösung

\int sec^{2} (x) + tan (x) d x

tan (x) - ln ∣ cos (x) ∣ + C

Schritte zur Lösung

\int sec^{2} (x) + tan (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec^{2} (x) d x + \int tan (x) d x

\int sec^{2} (x) d x = tan (x)

\int tan (x) d x = - ln ∣ cos (x) ∣

= tan (x) - ln ∣ cos (x) ∣

Füge eine Konstante zur Lösung hinzu

= tan (x) - ln ∣ cos (x) ∣ + C

\frac{d}{d x} (f (x) (3 x^{2} + 5))

\frac{\partial}{\partial x} (y^{2} - x)

in v erse l a pl a ce \frac{( 85 )}{( 18 s + 90 )}

\frac{d}{d x} (\frac{70 x}{( 3 x ^{2} + 8 ) ^{2}})

x \to \infty lim (\frac{x ^{2}}{e ^{4 x}})