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人気のある微分積分 >

(\partial)/(\partial x)(y^2-x)

解

\frac{\partial}{\partial x} (y^{2} - x)

解

- 1

解答ステップ

\frac{\partial}{\partial x} (y^{2} - x)

y

を定数として扱う

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (x)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x) = 1

= 0 - 1

簡素化

= - 1

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