(\partial ^2)/(\partial {u)(w)\partial w}(e^{{u}(w)-w})

Lösung

\frac{\partial ^{3}}{\partial u ( w ) \partial w ^{2}} (e^{u (w) - w})

Schritte zur Lösung

\frac{\partial ^{3}}{\partial u ( w ) \partial w ^{2}} (e^{u (w) - w})

\frac{\partial}{\partial u ( w )} (e^{u (w) - w}) = e^{u (w) - w}

= \frac{\partial ^{2}}{\partial w ^{2}} (e^{u (w) - w})

\frac{\partial}{\partial w} (e^{u (w) - w}) = e^{u (w) - w} (\frac{\partial}{\partial w} (u (w)) - 1)

= \frac{\partial}{\partial w} (e^{u (w) - w} (\frac{\partial}{\partial w} (u (w)) - 1))

\frac{\partial}{\partial w} (e^{u (w) - w} (\frac{\partial}{\partial w} (u (w)) - 1)) = e^{u (w) - w} (\frac{\partial}{\partial w} (u (w)) - 1)^{2} + e^{u (w) - w} \frac{\partial ^{2}}{\partial w ^{2}} (u (w))

= e^{u (w) - w} (\frac{\partial}{\partial w} (u (w)) - 1)^{2} + e^{u (w) - w} \frac{\partial ^{2}}{\partial w ^{2}} (u (w))

\int \frac{1}{( x - 1 ) ( x ^{2} + 9 )} d x

\int \frac{1}{9 - 4 x} d x

d er i v a t i v e y = \frac{- 12}{4 x}

2 x + y + (x + 2 y) y^{^{'}} = 0

\int - 2 x^{2} + 6 x d x