What is the integral of x7^{x^2} ?

The integral of x7^{x^2} is 1/(2ln(7))*7^{x^2}+C

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integral of x7^{x^2}

\int x 7^{x^{2}} d x

\frac{1}{2 ln ( 7 )} \cdot 7^{x^{2}} + C

Solution steps

\int x \cdot 7^{x^{2}} d x

Apply u-substitution

= \int \frac{1}{2 ln ( 7 )} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{2 ln ( 7 )} u

Substitute back

u = 7^{x^{2}}

= \frac{1}{2 ln ( 7 )} \cdot 7^{x^{2}}

Add a constant to the solution

= \frac{1}{2 ln ( 7 )} \cdot 7^{x^{2}} + C

y^{^{''}} + 14 \cdot 2 y^{^{'}} + 49 y = 0, y (0) = 0, y^{^{'}} (0) = 1

\int (\frac{8}{x}) d x

x \to 3 - lim (f (x))

a re a - x^{2}, 3 x - 10, x = 0

d er i v a t i v e \frac{e ^{x}}{8 x ^{2}}

What is the integral of x7^{x^2} ?
The integral of x7^{x^2} is 1/(2ln(7))*7^{x^2}+C