d/(dt)(at^2+bt+c)

Lösung

\frac{d}{d t} (a t^{2} + b t + c)

2 a t + b

Schritte zur Lösung

\frac{d}{d t} (a t^{2} + b t + c)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a t^{2}) + \frac{d}{d t} (b t) + \frac{d c}{d t}

\frac{d}{d t} (a t^{2}) = 2 a t

\frac{d}{d t} (b t) = b

\frac{d c}{d t} = 0

= 2 a t + b + 0

Vereinfache

= 2 a t + b

d er i v a t i v e 2

\int x sec^{4} (x^{2} + 1) tan^{7} (x^{2} + 1) d x

x \to 3 lim (\frac{5}{x ( x ^{3} - 27 )})

\int \frac{8 x}{x ^{3} + 1} d x

t an g e n t x sin (π x)