ty^'-3y=t^4

Lösung

t y^{^{'}} - 3 y = t^{4}

y = t^{4} + c_{1} t^{3}

Schritte zur Lösung

t y^{'} (t) - 3 y = t^{4}

Solve linear ODE:

y = t^{4} + c_{1} t^{3}

y = t^{4} + c_{1} t^{3}

\int \frac{x}{3 - x ^{2}} d x

\int \frac{x ^{2} - 2 x + 6}{( x + 1 ) ( x - 2 ) ^{2}} d x

d er i v a t i v e x^{2} (120 - x)

\int 10 sec^{2} (5 x) tan (5 x) d x

x \to \frac{π}{2} lim (x cos (x))