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Beliebt Rechnen >

y^{''}+12x=0,y(0)=-4,y^'(0)=5

Lösung

y^{^{''}} + 12 x = 0, y (0) = - 4, y^{^{'}} (0) = 5

Lösung

y = - 2 x^{3} + 5 x - 4

Schritte zur Lösung

y^{''} (x) + 12 x = 0

Isoliere

y^{''} (x) : y^{''} (x) = - 12 x

Löse

y^{''} (x) = - 12 x : y^{'} (x) = - 6 x^{2} + c_{1}

Löse

y^{'} (x) = - 6 x^{2} + c_{1} : y = - 2 x^{3} + c_{1} x + c_{2}

Wende die Anfangsbedingung an:

y = - 2 x^{3} + 5 x - 4

y = - 2 x^{3} + 5 x - 4

Graph

Beliebte Beispiele

(\partial)/(\partial x)((6y)/(x+y))

\frac{\partial}{\partial x} (\frac{6 y}{x + y})

integral of e^x*(1-e^x)^{-1}

\int e^{x} \cdot (1 - e^{x})^{- 1} d x

derivative of 2x^3e^x

\frac{d}{d x} (2 x^{3} e^{x})

derivative sqrt(3/x)

d er i v a t i v e \frac{3}{x}

derivative f(x)=x^3-2x+1

d er i v a t i v e f (x) = x^{3} - 2 x + 1