(dy)/(dx)=(x^3+y^3)/(3xy^2)

Lösung

\frac{d y}{d x} = \frac{x ^{3} + y ^{3}}{3 x y ^{2}}

y = 3 \frac{x ^{3}}{2} + c_{1} x

Schritte zur Lösung

\frac{d y}{d x} = \frac{x ^{3} + y ^{3}}{3 x y ^{2}}

Solve Bernoulli ODE:

y = 3 \frac{x ^{3}}{2} + c_{1} x

y = 3 \frac{x ^{3}}{2} + c_{1} x

t an g e n t f (x) = \frac{2}{x}, at x = 9

s l o p e (3.2) (- 1.2)

n = 1 \sum \infty \frac{n + 1}{n ^{2}}

\int \frac{2 x ^{2}}{1 - 4 x ^{3}} d x

\int_{0}^{1} 9 x e^{- x^{2}} d x