derivative 2/t-4/(t^2)

解答

导数

\frac{2}{t} - \frac{4}{t ^{2}}

- \frac{2}{t ^{2}} + \frac{8}{t ^{3}}

求解步骤

\frac{d}{d t} (\frac{2}{t} - \frac{4}{t ^{2}})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{2}{t}) - \frac{d}{d t} (\frac{4}{t ^{2}})

\frac{d}{d t} (\frac{2}{t}) = - \frac{2}{t ^{2}}

\frac{d}{d t} (\frac{4}{t ^{2}}) = - \frac{8}{t ^{3}}

= - \frac{2}{t ^{2}} - (- \frac{8}{t ^{3}})

化简

= - \frac{2}{t ^{2}} + \frac{8}{t ^{3}}

\int_{0}^{5} 40 e^{- 0.3 t} d t

y^{^{'}} = 7 x e^{y}, y (0) = 0

x \to 0 lim (\frac{a ^{x} - 1}{2 x})

x \to - \infty lim (4 x^{3})

x \to 0 lim (\frac{8}{x + 2})