derivative (2x)/(9x^2+1)

Lösung

ableitung von

\frac{2 x}{9 x ^{2} + 1}

\frac{2 ( - 9 x ^{2} + 1 )}{( 9 x ^{2} + 1 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{2 x}{9 x ^{2} + 1})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{9 x ^{2} + 1})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( 9 x ^{2} + 1 ) - \frac{d}{d x} ( 9 x ^{2} + 1 ) x}{( 9 x ^{2} + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (9 x^{2} + 1) = 18 x

= 2 \cdot \frac{1 \cdot ( 9 x ^{2} + 1 ) - 18 xx}{( 9 x ^{2} + 1 ) ^{2}}

Vereinfache

2 \cdot \frac{1 \cdot ( 9 x ^{2} + 1 ) - 18 xx}{( 9 x ^{2} + 1 ) ^{2}} : \frac{2 ( - 9 x ^{2} + 1 )}{( 9 x ^{2} + 1 ) ^{2}}

= \frac{2 ( - 9 x ^{2} + 1 )}{( 9 x ^{2} + 1 ) ^{2}}

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