derivative of cosh(x-(2e^{(-0.3x)}))

解答

\frac{d}{d x} (cosh (x) - (2 e^{(- 0.3 x)}))

sinh (x) + 0.6 e^{- 0.3 x}

求解步骤

\frac{d}{d x} (cosh (x) - (2 e^{(- 0.3 x)}))

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (cosh (x)) - \frac{d}{d x} (2 e^{- 0.3 x})

\frac{d}{d x} (cosh (x)) = sinh (x)

\frac{d}{d x} (2 e^{- 0.3 x}) = - 0.6 e^{- 0.3 x}

= sinh (x) - (- 0.6 e^{- 0.3 x})

化简

= sinh (x) + 0.6 e^{- 0.3 x}

\frac{d}{d y} (e^{x} \cdot sin (y))

d er i v a t i v e 4 y

y^{^{''}} - 10 y^{^{'}} + 25 y = 0

n = 0 \sum \infty \frac{2 ^{n}}{n + 1}

d er i v a t i v e \frac{s}{s ^{2} + 1}