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tangent 1/(x^2)(1.1)

解答

切线

\frac{1}{x ^{2}} (1.1)

解答

y = - \frac{2.2}{a _{0}^{3}} x + \frac{3.3}{a _{0}^{2}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{1.1}{a _{0}^{2}})

计算

y = \frac{1}{x ^{2}} 1.1

的斜率:

\frac{d y}{d x} = - \frac{2.2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2.2}{a _{0}^{3}}

找到斜率 m=

- \frac{2.2}{a _{0}^{3}}

且穿过

(a_{0}, \frac{1.1}{a _{0}^{2}})

的直线:

y = - \frac{2.2}{a _{0}^{3}} x + \frac{3.3}{a _{0}^{2}}

y = - \frac{2.2}{a _{0}^{3}} x + \frac{3.3}{a _{0}^{2}}

作图

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