(\partial)/(\partial y)(x^5+x^2y+x+2)

解答

\frac{\partial}{\partial y} (x^{5} + x^{2} y + x + 2)

x^{2}

求解步骤

\frac{\partial}{\partial y} (x^{5} + x^{2} y + x + 2)

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{5}) + \frac{\partial}{\partial y} (x^{2} y) + \frac{\partial}{\partial y} (x) + \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (x^{5}) = 0

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (2) = 0

= 0 + x^{2} + 0 + 0

化简

= x^{2}

\int \frac{1}{x} - e^{- x} d x

\int \frac{1}{4 x + 6 x} d x

n = 1 \sum \infty \frac{1}{2 n - 1}

x \frac{d y}{d x} = \frac{x ^{3}}{y} - \frac{5 x ^{5}}{y} - \frac{1}{x y}

t an g e n t f (x) = \frac{1}{x}, at x = 3