What is the d/(dθ)((cos(θ))/(sin(θ))) ?

The d/(dθ)((cos(θ))/(sin(θ))) is -csc^2(θ)

What is the first d/(dθ)((cos(θ))/(sin(θ))) ?

The first d/(dθ)((cos(θ))/(sin(θ))) is -csc^2(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d θ} (\frac{cos ( θ )}{sin ( θ )})

- csc^{2} (θ)

Solution steps

\frac{d}{d θ} (\frac{cos ( θ )}{sin ( θ )})

Simplify

\frac{cos ( θ )}{sin ( θ )} : cot (θ)

= \frac{d}{d θ} (cot (θ))

Apply the common derivative:

\frac{d}{d θ} (cot (θ)) = - csc^{2} (θ)

= - csc^{2} (θ)

d er i v a t i v e 2^{4 x}

\int 2 x 4 x^{2} + 1 d x

n = 0 \sum \infty \frac{2}{n ^{2} + 4 n + 3}

\int x - x^{2} d x

\frac{d}{d x} (\frac{- 4 x ^{6} + 4 x ^{5} - 3 x ^{3}}{3 x ^{2}})

What is the d/(dθ)((cos(θ))/(sin(θ))) ?
The d/(dθ)((cos(θ))/(sin(θ))) is -csc^2(θ)
What is the first d/(dθ)((cos(θ))/(sin(θ))) ?
The first d/(dθ)((cos(θ))/(sin(θ))) is -csc^2(θ)