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tangent f(x)=3x^2-x+7,\at x=2

解答

切线

f (x) = 3 x^{2} - x + 7, at x = 2

解答

y = 11 x - 5

求解步骤

找到切点:

(2, 17)

计算

f (x) = 3 x^{2} - x + 7

的斜率:

\frac{df ( x )}{d x} = 6 x - 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 11

找到斜率 m=

11

且穿过

(2, 17)

的直线:

y = 11 x - 5

y = 11 x - 5

作图

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