xln(2x)y^'-y=0

Lösung

x ln (2 x) y^{^{'}} - y = 0

y = c_{1} ln (2 x)

Schritte zur Lösung

x ln (2 x) y^{'} (x) - y = 0

Solve separable ODE:

y = c_{1} ln (2 x)

y = c_{1} ln (2 x)

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