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受欢迎的微积分 >

integral from 0 to 3 of 4e^{-3x}

解答

\int_{0}^{3} 4 e^{- 3 x} d x

解答

\frac{4 ( e ^{9} - 1 )}{3 e ^{9}}

+1

十进制

1.33316 \dots

求解步骤

\int_{0}^{3} 4 e^{- 3 x} d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{3} e^{- 3 x} d x

使用换元积分法

= 4 \cdot \int_{0}^{- 9} - \frac{1}{3} e^{u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= 4 (- \int_{- 9}^{0} - \frac{1}{3} e^{u} d u)

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 (- (- \frac{1}{3} \cdot \int_{- 9}^{0} e^{u} d u))

使用积分常见定则:

\int e^{u} d u = e^{u}

= 4 (- (- \frac{1}{3} [e^{u}]_{- 9}^{0}))

化简

4 (- (- \frac{1}{3} [e^{u}]_{- 9}^{0})) : \frac{4}{3} [e^{u}]_{- 9}^{0}

= \frac{4}{3} [e^{u}]_{- 9}^{0}

带入上下限计算后得:

1 - \frac{1}{e ^{9}}

= \frac{4}{3} (1 - \frac{1}{e ^{9}})

化简

= \frac{4 ( e ^{9} - 1 )}{3 e ^{9}}

作图

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