What is the tangent of f(x)=2sqrt(x),(1,2) ?

The tangent of f(x)=2sqrt(x),(1,2) is y=x+1

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tangent of f(x)=2sqrt(x),(1,2)

tangent of

f (x) = 2 x, (1, 2)

y = x + 1

Solution steps

Find the slope of

f (x) = 2 x : \frac{df ( x )}{d x} = \frac{1}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(1, 2) : y = x + 1

y = x + 1

\int \frac{4}{x ( x - 4 ) ^{2}} d x

x \to 1 + lim (arcsin (x))

\frac{d}{d x} (e^{2 x} (3 x - 2))

e x p an d (x^{3} - 4 x^{2} - 6 x + 1) (x^{2} - 3 x + 1)

\frac{d}{d x} (- sin (2 x) + 1)

What is the tangent of f(x)=2sqrt(x),(1,2) ?
The tangent of f(x)=2sqrt(x),(1,2) is y=x+1