What is the limit as x approaches 9 of ((x^2-4x-45))/(x^2-81) ?

The limit as x approaches 9 of ((x^2-4x-45))/(x^2-81) is 7/9

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limit as x approaches 9 of ((x^2-4x-45))/(x^2-81)

x \to 9 lim (\frac{( x ^{2} - 4 x - 45 )}{x ^{2} - 81})

\frac{7}{9}

Decimal

0.77777 \dots

Solution steps

x \to 9 lim (\frac{x ^{2} - 4 x - 45}{x ^{2} - 81})

Simplify

\frac{x ^{2} - 4 x - 45}{x ^{2} - 81} : \frac{x + 5}{x + 9}

= x \to 9 lim (\frac{x + 5}{x + 9})

Plug in the value

x = 9

= \frac{9 + 5}{9 + 9}

Simplify

\frac{9 + 5}{9 + 9} : \frac{7}{9}

= \frac{7}{9}

\int - 2 cos (t) sin^{2} (t) d t

\frac{d}{d x} (12 x^{2} + 4)

s l o p e in t erce pt (- 1, - 2), (- 2, 3)

\frac{d y}{d x} = \frac{- 2 y ^{2}}{x ^{2}}

\frac{d}{d t} (9 sin (t) - sin (9 t))

What is the limit as x approaches 9 of ((x^2-4x-45))/(x^2-81) ?
The limit as x approaches 9 of ((x^2-4x-45))/(x^2-81) is 7/9